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  • The equation of acute angle bisector between lines <img alt="(\sqrt{3}-1) y=(\sqrt{3}+1) x$ and $(\sqrt{3}+1) y=(\sqrt{3}-1) x" src="https://entrancecorner.oncodecogs.com/gif.latex?%28%5Csqrt%7B3%7

The equation of acute angle bisector between lines (\sqrt{3}-1) y=(\sqrt{3}+1) x$ and $(\sqrt{3}+1) y=(\sqrt{3}-1) x is

Option: 1

y=x


Option: 2

x+y=0


Option: 3

y=x+1


Option: 4

y=-x+1


Answers (1)

best_answer

 Give lines are \mathrm{y=\frac{\sqrt{3}+1}{\sqrt{3}-1} \mathrm{x} \: and \: \mathrm{y}=\frac{\sqrt{3}-1}{\sqrt{3}+1} \mathrm{x}}

Clearly inclination of both the lines with  the positive direction of x–axis  are 75^{\circ} and 15^{\circ} . Clearly the inclination of bisector will be 45^{\circ}. Hence its equation  is y = x.

Hence (A) is the correct answer.

 

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