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  • The equation of alternating current is <img alt="I=50 \sqrt{2} \sin \; 400 \; \pi\; \mathrm{t} \text { amp }" src="https://entrancecorner.oncodecogs.com/gif.latex?I%3D50%20%5Csqrt%7B2%7D%

The equation of alternating current is

I=50 \sqrt{2} \sin \; 400 \; \pi\; \mathrm{t} \text { amp }

Then the frequency and root mean square of current are respectively

Option: 1

\mathrm{200 \mathrm{~Hz}, 50 \mathrm{amp}}


Option: 2

\mathrm{400 \pi \: \mathrm{Hz}, 50 \sqrt{2} \: amp}


Option: 3

\mathrm{200 \mathrm{~Hz}, 50 \sqrt{2}\: amp }


Option: 4

\mathrm{50 \mathrm{~Hz}, 200 \: \mathrm{amp}}


Answers (1)

best_answer

\mathrm{\begin{aligned} & 2 \pi \mathrm{nt}=400 \pi \mathrm{t} \quad \therefore \mathrm{n}=200 \\ & I_o=50 \sqrt{2} \mathrm{amp} . \end{aligned}}

\mathrm{\text { R.m.s. current }=I_o / \sqrt{2}=50 \mathrm{amp} \text {. }}

Posted by

Irshad Anwar

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