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  • The equation of straight line (s) passing through ordered pairs (a, b) satisfying equation  <img alt="\sec ^2(a+2) b+a^2-1=0,-\pi<b<\pi" src="https://entrancecorner.oncode

The equation of straight line (s) passing through ordered pairs (a, b) satisfying equation  \sec ^2(a+2) b+a^2-1=0,-\pi<b<\pi and having slope \frac{1}{2}  is

 

Option: 1

x-2 y=0


Option: 2

x-2 y=\pi


Option: 3

x+2 y=1


Option: 4

x-2 y+\pi=0


Answers (1)

best_answer

\begin{aligned} \tan ^2(a+2) b+a^2 & =0 \\ a & =0, \tan ^2(a+2) b=0 \\ \Rightarrow \quad \tan ^2 2 b & =0 \Rightarrow b=0, \frac{\pi}{2},-\frac{\pi}{2} \\ (a, b) & =(0,0),\left(0, \frac{\pi}{2}\right),\left(0,-\frac{\pi}{2}\right) \\ y-0 & =\frac{1}{2}(x-0), y-\frac{\pi}{2}=\frac{1}{2}(x-0) \\ \text { nd } \quad \frac{\pi}{2} & =\frac{1}{2}(x-0) \\ 2 y & =x, 2 y-\pi=x, 2 y+\pi=x \end{aligned}

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Devendra Khairwa

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