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The equation of the bisector of the acute angle between the lines \mathrm{2 x-y+4=0} and \mathrm{x-2 y=1}

Option: 1

x+y+5=0


Option: 2

x-y+1=0


Option: 3

x-y=5


Option: 4

x+y+1=0


Answers (1)

best_answer

Its quits clear from the figure that origin is contained in the acute angle

Hence the required bisector is

\frac{2 x-y+4}{\sqrt{5}}=\frac{-x+2 y+1}{\sqrt{5}} \\
\Rightarrow x-y+1=0


 

 

Posted by

HARSH KANKARIA

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