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  • The equation of the chord of the hyperbola   which is b

The equation of the chord of the hyperbola \mathrm{25 x^2-16 y^2=400}  which is bisected at (5,3) is \mathrm{125 x-48 y=k+480}, then \mathrm{k=} __________.

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

best_answer

The equation of hyperbola is 25 x^2-16 y^2=400 i.e.,

 \frac{x^2}{16}-\frac{y^2}{25}=1

Equation of chord is T=S_1

\frac{5 x}{16}-\frac{3 y}{25}-1=\frac{25}{16}-\frac{9}{25}-1

On simplifying, we get 125 x-48 y=481 \therefore k=1.

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