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  • The equation of the circumcircle of the triangle formed by the lines <img alt="\mathrm{y+\sqrt{3} x=6, y-\sqrt{3} x=6}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7By&plus;%

The equation of the circumcircle of the triangle formed by the lines \mathrm{y+\sqrt{3} x=6, y-\sqrt{3} x=6} and \mathrm{y=0} is

Option: 1

\mathrm{x^{2}+y^{2}-4 y=0}


Option: 2

\mathrm{x^{2}+y^{2}+4 x=0}


Option: 3

\mathrm{x^{2}+y^{2}-4 y=12}\mathrm{x^{2}+y^{2}+4 x=12}


Option: 4

\mathrm{x^{2}+y^{2}+4 x=12}


Answers (1)

best_answer

The three vertices by solving in pairs are (0,6),(2 \sqrt{3}, 0)\: and \: (-2 \sqrt{3}, 0 )  if the circle be g, f, c ,then g=0, f=-2, c=-12.

Hence (C) is the correct answer.

 

Posted by

Pankaj Sanodiya

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