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  • The equation of the hyperbola with vertices (3, 0) and (−3, 0) and semi latus rectum 4, is given by    <st

The equation of the hyperbola with vertices (3, 0) and (−3, 0) and semi latus rectum 4, is given by

 

 

Option: 1

\mathrm{4 x^2-3 v^2+36=0}


Option: 2

\mathrm{4 x^2-3 y^2+12=0}


Option: 3

\mathrm{4 x^2-3 y^2-36=0}


Option: 4

none of these 

 


Answers (1)

best_answer

\mathrm{\text { We have, } a=3 \text { and } \frac{b^2}{a}=4 \Rightarrow b^2=12 \text {. }}

Hence, the equation of the hyperbola is \mathrm{\frac{x^2}{9}-\frac{y^2}{12}=1 \Rightarrow 4 x^2-3 y^2=36}

Posted by

manish painkra

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