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  • The equation of the image of the circle <img alt="\mathrm{x^{2}+y^{2}+16 x-24 y+183= 0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bx%5E%7B2%7D&plus;y%5E%7B2%7D&plus;1

The equation of the image of the circle \mathrm{x^{2}+y^{2}+16 x-24 y+183= 0} by the line mirror \mathrm{4 x+7 y+13=0} is

Option: 1

\mathrm{x^{2}+y^{2}+32 x-4 y+235=0}


Option: 2

\mathrm{x^{2}+y^{2}+32 x+4 y-235=0}


Option: 3

\mathrm{x^{2}+y^{2}+32 x-4 y-235=0}


Option: 4

\mathrm{x^{2}+y^{2}+32 x+4 y+235=0}


Answers (1)

best_answer

Image of the centre =(-16,-2)

So equation of required circle is
\mathrm{(x+16)^{2}+(y+2)^{2}=5^{2}}

Hence (D) is the correct answer.

Posted by

Sanket Gandhi

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