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  • The equation of the line through the intersection of the lines <img alt="\mathrm{2 x+3 y+4=0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2%20x&

The equation of the line through the intersection of the lines \mathrm{2 x+3 y+4=0} and
\mathrm{6 x-3 k+12=0} and normal to the circle \mathrm{x^2+y^2-4 x-12=0,} is

 

Option: 1

x = y


Option: 2

x = 0

 


Option: 3

y = 0


Option: 4

None of these

 


Answers (1)

best_answer

Equation of line is\mathrm{(2 x+3 y+4)+\lambda(6 x-3 y+12)=0}    …(1)

(1) is normal to circle, therefore (1) passes through (2, 0)

\mathrm{\Rightarrow \lambda=\frac{-1}{3}} and required equation is y = 0.

 

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