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The equations of any tangents to the circle  x^2+y^2-2 x+4 y-4=0 is

Option: 1

y=m(x-1)+3 \sqrt{1+m^2}-2


Option: 2

y=m x+3 \sqrt{1+m^2}


Option: 3

y=m x+3 \sqrt{1+m^2}-2


Option: 4

None of these


Answers (1)

best_answer

Equation of circle is (x-1)^2+(y+2)^2=3^2

As any tangent to x^2+y^2=3^2 is given by y=m x+3 \sqrt{1+m^2}

Any tangent to the given circle will be y+2=m(x-1)+3 \sqrt{1+m^2} \Rightarrow y=m(x-1)+3 \sqrt{1+m^2}-2

Posted by

Ritika Jonwal

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