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The equation(s) of the tangent at the point (0, 0) to the circle, making intercepts of length 2a and 2b units on the coordinate axes, is (are)

Option: 1

\mathrm{a x+b y=0}


Option: 2

\mathrm{a x-b y=0}


Option: 3

\mathrm{x=y}


Option: 4

None of these

 


Answers (1)

best_answer

Equation of circle passing through origin and cutting off intercepts 2a and 2b units on the coordinate axes is

\mathrm{x^2+y^2 \pm 2 a x \pm 2 b y=0}

and equation of tangent at (0, 0) is

\mathrm{a x \pm b y=0}

 

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Divya Prakash Singh

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