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The expansion of \frac{1}{(4-3 x)^{1 / 2}} binomial theorem will be valid, if

Option: 1

x<1


Option: 2

|x|<1


Option: 3

-\frac{2}{\sqrt{3}}<x<\frac{2}{\sqrt{3}}


Option: 4

None of these


Answers (1)

best_answer

The given expression can be written as

4^{-1 / 2}\left(1-\frac{3}{4} x\right)^{-1 / 2}and it is valid only when


\left|\frac{3}{4} x\right|<1 \Rightarrow-\frac{4}{3}<x<\frac{4}{3}
 

Posted by

Pankaj Sanodiya

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