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  • The extension in a string obeying Hookers law is . The speed of transerse wave in the stretched string

The extension in a string obeying Hookers law is \mathrm{x}. The speed of transerse wave in the stretched string is \mathrm{v}. If the extension in the string is increased to \mathrm{1.5x}, the speed of transverse waves in it will be -
 

Option: 1

\mathrm{1.22\: v}


Option: 2

\mathrm{2\: v}


Option: 3

\mathrm{1.5\: v}


Option: 4

\mathrm{\: v}


Answers (1)

best_answer

\mathrm{v \propto \sqrt{T} \Rightarrow v^{\prime}=\sqrt{1.5} \cdot v=1.22 \mathrm{~V} }

Hence option v is correct.
 

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