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The father has seven different presents that he is considering giving to his four sons. However, he decided to keep his present for himself. How many ways can he distribute the remaining presents?

Option: 1

8970


Option: 2

8930


Option: 3

8940


Option: 4

8960


Answers (1)

best_answer

Given that,

Number of presents, \mathrm{n= 7}
Number of sons, \mathrm{r=4}

Therefore, total number of ways

\mathrm{ =\left(\begin{array}{l} 7 \\ 4 \end{array}\right)(4)^{4}}
\mathrm{ =35 \times 256}
\mathrm{ =8960}

Posted by

sudhir.kumar

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