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The figure shows a meter-bridge circuit, X=12\; \Omega and X=18\; \Omega . The jockey J is in the position of balance. If R is made 8\; \Omega , through what distance will the jockey J have to be moved to obtain balance?

Option: 1

10 cm


Option: 2

20 cm


Option: 3

30 cm


Option: 4

40 cm


Answers (1)

best_answer

Let the distance AJ be y_{1} before shifting and y_{2} after shifting.

Before shifting: \frac{12}{y_{1}}=\frac{18}{100-y_{1}}\Rightarrow y_{1}=40 cm

After shifting: \frac{12}{y_{2}}=\frac{18}{100-y_{2}}\Rightarrow y_{2}=40 cm

\therefore Distance moved = 20 cm

Posted by

Ajit Kumar Dubey

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