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  • The first line of Balmer series has wavelength 6563 Å.What will be the wavelength of the first member of Lyman seriesOption: 1 1215.4 Å</

The first line of Balmer series has wavelength 6563 Å.What will be the wavelength of the first member of Lyman series

Option: 1

1215.4 Å


Option: 2

2500 Å


Option: 3

7500 Å


Option: 4

600 Å


Answers (1)

best_answer

\mathrm{\frac{1}{\lambda_{\text {Balmer }}}=R\left[\frac{1}{2^2}-\frac{1}{3^2}\right]=\frac{5 R}{36}, \frac{1}{\lambda_{\text {Lyman }}}=R\left[\frac{1}{1^2}-\frac{1}{2^2}\right]=\frac{3 R}{4}}
\mathrm{ \therefore \lambda_{\text {Lyman }}=\lambda_{\text {Balmer }} \times \frac{5}{27}=1215.4 \AA}

Posted by

Divya Prakash Singh

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