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  • The following equation represents an ellipse <img alt="\mathrm{25\left(x^2-6 x+9\right)+16 y^2=400}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B25%5Cleft%28x%5E2-6%20x&plu

The following equation represents an ellipse \mathrm{25\left(x^2-6 x+9\right)+16 y^2=400} the centre and the foci of the ellipse are

Option: 1

\mathrm{(3,0), e=3 / 5}


Option: 2

\mathrm{(3,0), e=1 / 3}


Option: 3

\mathrm{(0,3), e=\sqrt{3} / 5}


Option: 4

\mathrm{(3,0), e=\sqrt{3} / 5}


Answers (1)

best_answer

\mathrm{\frac{(x-3)^2}{4^2}+\frac{y^2}{5^2}=1}

\mathrm{\frac{X^2}{b^2}+\frac{Y^2}{a^2}=1}

\mathrm{a^2>b^2} i.e., major axis is along y-axis . Centre is (3,0)

\mathrm{ e^2=1-\left(\frac{b^2}{a^2}\right)=1-\frac{16}{25} \therefore e=\frac{3}{5} }

Posted by

Gautam harsolia

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