Get Answers to all your Questions

header-bg qa

The force on a body moving along the x-axis varies with position as shown in the figure. The body is in stable equilibrium when:

Option: 1

At A

 

 


Option: 2

At B

 

 


Option: 3

At C

 

 


Option: 4

None of A, B and C

 

 


Answers (1)

best_answer

For a stable balance,

\frac{d F}{d x}<0 i.e. negative slope in the graph F and x

At point A,

\theta is less than 90^{\circ},so slope \tan \theta is positive.

At point B,

\theta is 0^{\circ}, So slope \tan \theta is zero.

At point C,

\theta is more than 90^{\circ}. So slope \tan \theta is negative

So, at point at C  \frac{d F}{d x}<0 i.e the point of stable equilibrium.

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE