The function f (x) = 1 + |sin x| is
continuous nowhere
continuous everywhere
discontinuous at x = 0
None of these
f (x) = 1 + |sin x|
where sin x > 0 ⇒ f (x) = 1 + sin x
sin x < 0 ⇒ f (x) = 1 − sin x
so continuous every where
Hence (B) is the correct answer.
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