Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The function  <img alt="\mathrm{h(x)=\sin ^{-1} x-\cos ^{-1} \sqrt{1-x^2} }" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bh%28x%29%3D%5Csin%20%5E%7B-1%7D%20x-%5Ccos%20%5E%7

The function  \mathrm{h(x)=\sin ^{-1} x-\cos ^{-1} \sqrt{1-x^2} } in its entire domain is 

Option: 1

an increasing function
 


Option: 2

a decreasing function
 


Option: 3

a non-increasing function
 


Option: 4

a non-decreasing function


Answers (1)

\mathrm{h(x)= \begin{cases}2 \sin ^{-1} x, & x<0 \\ 0, & x \geq 0\end{cases}}

\mathrm{\Rightarrow \mathrm{h}(\mathrm{x}) \text { is non-decreasing function. }}

Posted by

Ramraj Saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA 2025 reconstituted; NIT Rourkela to coordinate BTech counselling for IITs, NITs, IIITs
anam-khan

JEE Main 2025: BTech Information Technology cut-offs at NITs; know opening, closing ranks
anam-khan

JEE Main 2025: BTech Computer Science Engineering cut-offs at NITs went up this year

Latest Question