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The given figure represents an arrangement of potentiometer for the calculation of internal resistance (r) of the unknown battery (E). The balance length is $70.0 \mathrm{~cm}$ with the key opened and $60.0 \mathrm{~cm}$ with the key closed. $\mathrm{R}$ is 132.40 $\Omega$ . The internal resistance (r) of the unknown cell to a correct number of significant figures. $\left(\mathrm{E}_0>\mathrm{E}\right)$ is $\mathrm{xy}$ . $1 \Omega$ , The values of digit $\mathrm{x}$ is :

Option: 1
1

Option: 2
2

Option: 3
3

Option: 4
4

Answers (1)

best_answer

Internal resistance $r=\frac{\mathrm{R}\left[\ell-\ell^{\prime}\right]}{\ell^{\prime}}$

where $\ell=$ balanced length with key open.

$\ell^{\prime}=$ balanced length with key $\mathrm{K}$ closed

. $\therefore \quad r=\frac{132.40[70-60]}{60}$

$=\frac{132.40 \times 10}{60}=22.0666 \Omega$

$=22 \cdot 1 \Omega \text {. Thus } x=2$

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