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The ground state energy of hydrogen atom is \mathrm{-13.6\ ev} the kinetic and potential energy of the electron in the second exicited state is respectively -

Option: 1

\mathrm{-1.51\ ev, +\ 3.02\ ev}


Option: 2

\mathrm{+3.2\ ev, +1.51\ ev}


Option: 3

\mathrm{1.51\ ev, -3.2\ ev}


Option: 4

\mathrm{+3.02\ ev , -1.51\ ev}


Answers (1)

best_answer

Use \mathrm{n^{th}} energy of \mathrm{H} - atom \mathrm{E_n=\frac{-13.6}{(3)^2}=-1.51\ \mathrm{ev}}
Kinetic energy  \mathrm{\left ( K.E. \right )=-E_{n}=+1.51\ ev}
Potential energy 
\mathrm{\begin{aligned} (P E) & =2\ E_n \\ & =2 \times(+1.5 / \mathrm{eV}) \\ & =-3.02\ \mathrm{eV} \end{aligned}}

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