Get Answers to all your Questions

header-bg qa

The hydroxyl group at which carbon is involved in ring formation of glucose?

 

Option: 1

\mathrm{C_{3}}


Option: 2

\mathrm{C_{4}}


Option: 3

\mathrm{C_{5}}


Option: 4

\mathrm{C_{6}}


Answers (1)

best_answer

Monosaccharides undergo intramolecular reaction to form cyclic hemiacetal structure. Generally, in aldoses, the \mathrm{\mathrm{C}_4} or \mathrm{\mathrm{C}_5}carbon is involved in cyclisation. In glucose, the hemiacetal (six-membered ring) is formed between the \mathrm{\mathrm{CHO}} group and the \mathrm{\mathrm{OH}} group on the \mathrm{\mathrm{C}_5} carbon.

Posted by

Ajit Kumar Dubey

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE