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  • The image of a point in the line <img alt="x+3 y-7=0" src="https://entrancecorner.oncodecogs.com/gif.latex?x&

The image of a point A(3,8) in the line x+3 y-7=0, is

Option: 1

(-1,-4)


Option: 2

(-3,-8)


Option: 3

(1,-4)


Option: 4

(3, 8)


Answers (1)

best_answer

Equation of the line passing through (3, 8) and perpendicular to x+3 y-7=0 is 3 x-y-1=0.

The intersection point of both the lines is (1, 2). Now let the image of A(3,8) be A^{\prime}\left(x_1, y_1\right)

The point (1, 2) will be the midpoint of

A A^{\prime} \cdot \frac{x_1+3}{2}=1 \Rightarrow x_1=-1  and \frac{y_1+8}{2}=2 \Rightarrow y_1=4

Hence the image is (-1,-4)

 

Posted by

Ajit Kumar Dubey

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