Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The image of point p when viewed from top of the slabs will be  (both top slab and bottom slab has refractive index=<img alt="\mu=1.5" src="https://entrancecorner.oncodecogs.com/gif.

The image of point p when viewed from top of the slabs will be 

(both top slab and bottom slab has refractive index=\mu=1.5)

Option: 1

2 cm above p


Option: 2

1.5 cm above p


Option: 3

2 cm below p


Option: 4

1 cm above p


Answers (1)

best_answer

As we learn

Apparent Shift (Δd) -

\Delta d=d\left ( 1-\frac{n_{r}}{n_{i}} \right )
 

- wherein

n_{i} = Refractive index of medium of incident.

n_{r} = Refractive index of medium of refraction.

d = distance of object.

 

 

d= 2(1-\frac{1}{\mu })t=2(1-\frac{1}{1.5})(1.5)cm

= 1.0 cm

Therefore final image will be 1 cm above point p.

Posted by

Divya Prakash Singh

View full answer

Similar Questions