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The intensity of sound at a point due to a point source is 0.2 w/m^2. If the distance of the source is made doubled and the power is also doubled, then the intensity at the point will be-

Option: 1

0.05 \mathrm{w} / \mathrm{m}^2


Option: 2

0.1 \mathrm{w} / \mathrm{m}^2


Option: 3

0.2 \mathrm{w} / \mathrm{m}^2


Option: 4

0.4 \mathrm{w} / \mathrm{m}^2


Answers (1)

best_answer

Due to a point source,

\begin{aligned} & \quad I_r=\frac{\rho}{4 \pi r^2} \\ & \therefore \quad I_r \propto \frac{\rho}{r^2} \end{aligned}

If \rho and r both doubled, I_r will remain half

Posted by

Devendra Khairwa

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