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  • The ionic radii of <img alt="\mathrm{O}^{2-}, \mathrm{F}^{-}, \mathrm{Na}^{+} \text {and } \mathrm{Mg}^{2+}" src="/latex-image/?%5Cmathrm%7BO%7D%5E%7B2-%7D%2C%20%5Cmathrm%7BF%7D%5E%7B-%7D%2C%20%5Cmathrm%7BNa%7D%5E%7B&plus;%7D%20%5Ctext%20%7Band%2

The ionic radii of \mathrm{O}^{2-}, \mathrm{F}^{-}, \mathrm{Na}^{+} \text {and } \mathrm{Mg}^{2+} are in order:
Option: 1 \mathrm{F}^{-}>\mathrm{O}^{2-}>\mathrm{Na}^{+}>\mathrm{Mg}^{2+}
Option: 2 \mathrm{O^{2-}>F^{-}>Na^{+}>Mg^{2+}}
Option: 3 \mathrm{Mg^{2+}>Na^{+}>F^{-}>O^{2-}}
Option: 4 \mathrm{O^{2-}>F^{-}>Mg^{2+}>Na^{+}}

Answers (1)

best_answer

We know these about ions-

We know as (z/e) ratio increases size decreases.

Thus correct ionic radii order is

\mathrm{O}^{-2}>\mathrm{F}^{-}>\mathrm{Na}^{+}>\mathrm{Mg}^{2+}

Therefore, the correct option is (2).

Posted by

Kuldeep Maurya

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