Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The line intersects the circle <img alt="\mathrm{x^2+y^2=9}" src="https://en

The line \mathrm{y=2 x+5} intersects the circle \mathrm{x^2+y^2=9} at points A and B, then the locus of point ' C ' such that \mathrm{AC}  is  perpendicular to \mathrm{BC} is
 

Option: 1

\mathrm{ x^2+y^2+2 x-y-4=0 }


Option: 2

\mathrm{ x^2+y^2-4 x+2 y-19=0 }


Option: 3

\mathrm{ x^2+y^2+4 x-2 y+1=0 }


Option: 4

\mathrm{x^2+y^2+4 x+2 y-10=0 }


Answers (1)

best_answer

The locus of '\mathrm{C} ' is a circle with diameter \mathrm{\mathrm{AB}}. Let equation of circle is \mathrm{x^2+y^2-9+\lambda(2 x-y+5)=0} centre \mathrm{\left(-\lambda, \frac{\lambda}{2}\right)} lie on \mathrm{2 x-y+5=0 \Rightarrow \lambda=2}

Posted by

manish

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question