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  • The locus of point of intersection of perpendicular tangents of the hyperbola <img alt="\mathrm{4 y^2=x^2-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmath

The locus of point of intersection of perpendicular tangents of the hyperbola \mathrm{4 y^2=x^2-1}, is

 

Option: 1

\mathrm{4 x^2+4 y^2-3=0}


Option: 2

\mathrm{2 x^2+2 y^2-5=0}


Option: 3

\mathrm{3 x^2+3 y^2-4=0}


Option: 4

none of these

 


Answers (1)

best_answer

The hyperbola \mathrm{4 y^2=x^2-1} can be rewritten as \mathrm{\frac{x^2}{1}-\frac{y^2}{1 / 4}=1}, so its director circle will be \mathrm{x^2+y^2=1-\frac{1}{4}}

 

Posted by

Kuldeep Maurya

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