Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The locus of the centers of the circle passing through the intersection of the circles <img alt="\mathrm{x^2+y^2=1}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bx%5E2&

The locus of the centers of the circle passing through the intersection of the circles \mathrm{x^2+y^2=1} and  \mathrm{x^2+y^2-2 x+y=0} is 

Option: 1

a line whose equation is \mathrm{x+2 y=0}


Option: 2

a line whose equation is \mathrm{2 x-y=1}


Option: 3

a circle 


Option: 4

a pair of lines 


Answers (1)

best_answer

Any circle passing through the points of intersection of the given circles is \mathrm{x^2+y^2-2 x+y+\lambda\left(x^2+y^2-1\right)=0}

. If \mathrm{(\alpha, \beta)} be its centre then

\mathrm{ \alpha=\frac{1}{1+\lambda}, \beta=\frac{-1 / 2}{1+\lambda} \Rightarrow \alpha+2 \beta=0 }

Posted by

Shailly goel

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question