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  • The locus of the mid point of chord of the circle   such that

The locus of the mid point of chord of the circle \mathrm{x^2+y^2=9}  such that segment intercepted by the chord on the curve \mathrm{y}^2-4 \mathrm{x}-4 \mathrm{y}=0  subtends the right angle at the origin is
 

Option: 1

\mathrm{ x^2+4 x+4 y-9=0}


Option: 2

\mathrm{ x^2+y^2+4 x+4 y=0}


Option: 3

\mathrm{ x^2+y^2-4 x-4 y=0}


Option: 4

\mathrm{x^2+y^2-4 x-4 y-9=0}


Answers (1)

best_answer

equation of chord whose mid point is ( h, k) is
\mathrm{h} \mathrm{x}+\mathrm{ky}=\mathrm{h}^2+\mathrm{k}^2making homogenous eq with parabola
\begin{aligned} & \mathrm{y^2-4(x+y) \frac{(h x+k y)}{h^2+k^2}=0 }\\ & \text { Coeff }\mathrm{ x^2}+\text { coeff }\mathrm{ y^2=0} \quad \mathrm{h^2+k^2=4(h+k)} \end{aligned}
 

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