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The         logical         statement  (p\Rightarrow q)\wedge (q\Rightarrow \sim p) is equivalent to :
Option: 1 \sim p  
Option: 2 p
Option: 3 q
Option: 4 \sim q

Answers (1)

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Practise Session - 2 -

Q1. Write the truth table for the following statement pattern:
        \\ \mathrm{1.\;\;\;\sim(p \vee((\sim q \Rightarrow q) \wedge q))}\\\mathrm{2.\;\;\;(p\wedge q)\vee(\sim r)}\\

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\begin{array}{c|c|ccc}{\mathbf{p}} & {\mathbf{q}} & {((\mathbf{p} \rightarrow \mathbf{q})} & {\mathbf{\wedge}(\mathbf{q} \rightarrow \neg \mathbf{p}))} & {} \\ \hline F & {F} & {} & {\mathbf{T}} \\ \hline F & {T} & {} & {\mathbf{T}} \\ \hline T & {F} & {} & {F} \\ \hline T & {T} & {} & {F}\end{array}

which is equal to \sim p

Correct Option (1)

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Ritika Jonwal

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