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The magnetic flux through a coil perpendicular to its plane and directed into paper is varying according to the
relation \mathrm{\phi=\left(2 t^2+4 t+6\right) m W b} . The emf induced in the loop at t = 4 s is: 

Option: 1

0.12 V


Option: 2

2.4 V


Option: 3

0.02 V


Option: 4

1.2 V


Answers (1)

best_answer

\mathrm{Given, \phi=\left(2 \mathrm{t}^2+4 \mathrm{t}+6\right) \mathrm{mWb}}

\mathrm{As, \varepsilon=\frac{\mathrm{d} \phi}{\mathrm{dt}}=\frac{\mathrm{d}}{\mathrm{dt}}\left(2 \mathrm{t}^2+4 \mathrm{t}+6\right) \times 10^{-3} \mathrm{Wbs}^{-1}=(4 \mathrm{t}+4) \times 10^{-3} \mathrm{~V}}

\mathrm{At \; \mathrm{t}=4 \mathrm{~s}}

\mathrm{\varepsilon=(4 \times 4+4)=\times 10^3 \mathrm{~V}=20 \times 10^{-3} \mathrm{~V}=0.02 \mathrm{~V}}

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Ajit Kumar Dubey

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