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The mean free path of molecules of a certain gas at STP is 1500d, where d is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at 373 K is approximately :
 

Option: 1

750d 


Option: 2

1500d 


Option: 3

1098d 


Option: 4

2049d


Answers (1)

best_answer

mean free path \lambda

\begin{aligned} & \lambda=\frac{\mathrm{RT} }{\sqrt{2} \Pi \mathrm{d}^2 \mathrm{~N}_{\mathrm{A}} \mathrm{P}} \\ & \lambda \propto \mathrm{T} \\ & \frac{1500 \mathrm{~d}}{\lambda}=\frac{273}{373} \\ & \lambda=2049 \mathrm{~d} \end{aligned}

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shivangi.bhatnagar

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