Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The megnetic field in a region is given by <img alt="\overrightarrow{B}=B_o\left ( \frac{x}{a} \right )\hat{k}." src="https://entrancecorner.codecogs.com/gif.latex?%5Coverrightarrow%7BB%7D%3DB_o%5Cleft%20%28%20%5Cfrac%7Bx%7D%7Ba%7D%20%5Cright%20%29%5Ch

The megnetic field in a region is given by \overrightarrow{B}=B_o\left ( \frac{x}{a} \right )\hat{k}.A square loop of side d is placed with its edges along the x and y axes. The loop is moved with a constant velocity \overrightarrow{v}=v_o\;\hat{i}.The emf induced in the loop is :   
Option: 1 \frac{B_ov_od}{2a}
 
Option: 2   \frac{B_ov_{o}^{2}d^{2}}{a}
Option: 3 \frac{B_ov_od^{2}}{2a}  
Option: 4 \frac{B_ov_od^{2}}{a}

Answers (1)

best_answer

\begin{array}{l} \mathrm{E}_{1}=\frac{\mathrm{B}_{0}(\mathrm{x}+\mathrm{d})}{\mathrm{a}} \mathrm{v}_{0} \mathrm{~d} \\ \mathrm{E}_{2}=\frac{\mathrm{B}_{0}(\mathrm{x})}{\mathrm{a}} \mathrm{v}_{0} \mathrm{~d} \\ \mathrm{E}_{\mathrm{net}}=\mathrm{E}_{1}-\mathrm{E}_{2} \\ \Rightarrow \mathrm{E}_{\mathrm{net}}=\frac{\mathrm{B}_{0} \mathrm{v}_{0} \mathrm{~d}^{2}}{\mathrm{a}} \end{array}

 

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon; paper pattern, exams from January 22
anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon at jeemain.nta.nic.in

Latest Question