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  • The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is <img alt="\ma

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:

[Given: The threshold frequency of platinum is \mathrm{1.3 \times 10^{15}s^{-1}} and \mathrm{h=6.6\times 10^{-34}Js.}]

Option: 1

3.21\times 10^{-14}J


Option: 2

6.24\times 10^{-16}J


Option: 3

8.58\times 10^{-19}J


Option: 4

\mathrm{9.76\times 10^{-20}}J


Answers (1)

best_answer

\begin{aligned} \text { Minimum Energy }&= \text {h} \times \text{threshold frequency }\\ &=\mathrm{h \times \nu_0} \\ &=6.6 \times 10^{-14} \times 1.3 \times 10^{15} \mathrm{~J} \\ &=8.58 \times 10^{-19} \mathrm{~J} \end{aligned}

Hence, the correct answer is Option (3)

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