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  • The momentum of a photon of energy 1 MeV in Kg m/s. will beOption: 1 <img alt="0.33\times10^{6}" src="https://entrancecorner.oncodecogs.com/gif.latex

The momentum of a photon of energy 1 MeV in Kg m/s. will be

Option: 1

0.33\times10^{6}


Option: 2

7\times10^{-24}


Option: 3

10^{-22}


Option: 4

5\times10^{-22}


Answers (1)

best_answer

The momentum of a photon is given by:
p= \frac{E}{c}

where E is the energy of the photon and c is the speed of light in a vacuum.
Substituting E=1 \mathrm{MeV}=1.6 \times 10^{-13} \mathrm{~J}
c=2.998 \times 10^8 \mathrm{~m} / \mathrm{s},
We get:
p=\frac{1.6 \times 10^{-13} \mathrm{~J}}{2.998 \times 10^8 \mathrm{~m} / \mathrm{s}} \approx 5.34 \times 10^{-22} \mathrm{~kg} \mathrm{~m} / \mathrm{s}

Posted by

Irshad Anwar

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