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 The number of five digit numbers that can be formed by using digits 1, 2, 3 only, such that three digits of the formed number are identical, is

Option: 1

30


Option: 2

60


Option: 3

90


Option: 4

none of these.


Answers (1)

best_answer

When exactly three digits are identical and the remaining two are different, then the number of such numbers

\mathrm{\left({ }^{3} C_{1}\right)\left(\frac{5 !}{3 !}\right)=60}

When three digits are identical and the remaining two are also identical, then the number of ways

\mathrm{=\left({ }^{3} C_{2}\right)\left(\frac{5 !}{3 ! 2 !}\right)=30}

Thus, the number of such numbers \mathrm{=90}.

Posted by

HARSH KANKARIA

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