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  • The number of geometrical isomers possible in triamminetrinitrocobalt (III) is and in trioxalatochromate (III) is <img alt="\mathrm{Y}" src="https://entrancecorn

The number of geometrical isomers possible in triamminetrinitrocobalt (III) is \mathrm{X} and in trioxalatochromate (III) is \mathrm{Y}. Then the value of \mathrm{X}+\mathrm{Y} is_______.
 

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\text { Complex 1: } \left[\mathrm{CO}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{2}\right]

is of type \text{Ma}_{3}\text{b}_{3}.  It has two geometrical isomers - facial and meridional

\text { Complex 2: }\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-} is of type [\text{M}(\text{AA})_{3}] and it has no geometric isomer as bidentate ligands can only attach through cis - positions.

Thus, x=2, \quad y=0

Hence, the correct answer is  (2).

Posted by

sudhir.kumar

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