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The number of moles of sulphur produced when 2 moles of H_{2}S reacts with KMnO_{4} in sulphuric acid is:

Option: 1

7/3

 


Option: 2

2

 


Option: 3

8/3

 


Option: 4

4/3


Answers (1)

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The reaction is:  3 \mathrm{H}_2 \mathrm{~S}+\mathrm{KMnO}_4+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{K}_2 \mathrm{SO}_4+\mathrm{MnSO}_4+4 \mathrm{~S}

So, 3 moles of \mathrm{H}_2 \mathrm{~S} reacts to give 4 moles of Sulphur.

1 mole of \mathrm{H}_2 \mathrm{~S} can give 4/3 moles of sulphur.

2 moles of \mathrm{H}_2 \mathrm{~S} can give 4/3 X 2 = 8/3 moles of sulphur.

 

Posted by

Divya Prakash Singh

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