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  • The number of points of non-differentiability of <img alt="\mathrm{f(x)=\max \{\sin x, \cos x, 0\}\, in\, (0,2 n \pi)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bf%28x%29%3D%

The number of points of non-differentiability of \mathrm{f(x)=\max \{\sin x, \cos x, 0\}\, in\, (0,2 n \pi)} is

Option: 1

0


Option: 2

n


Option: 3

2n


Option: 4

3n


Answers (1)

best_answer

Here period of f(x) is \mathrm{2 \pi} and in \mathrm{(0,2 \pi)} the points of non differentiability are \mathrm{x=\frac{\pi}{4}, \pi} and \mathrm{\frac{3 \pi}{2}.}
So the total number of points of non-differentiability \mathrm{=3 n.}

Posted by

Ritika Jonwal

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