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The number of terms in the expansion of \small (a+b+c)^n  will be
 

Option: 1

n+1


Option: 2

n+3


Option: 3

\frac{(n+1)(n+2)}{2}


Option: 4

None of these


Answers (1)

By converse rule, put n= 1, 2, then number of terms are 3, 6. 
Hence number of terms of  (a+b+c)^n=\frac{(n+1)(n+2)}{2}

Posted by

Kshitij

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