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The number of turns in primary and secondary coils of a transformer is 50 and 200. If the current in the primary coil is 4 A, then the current in the secondary coil is:

Option: 1

1 A


Option: 2

2 A


Option: 3

4 A


Option: 4

5 A


Answers (1)

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Here,\mathrm{ \mathrm{N}_{\mathrm{p}}=50, \mathrm{~N}_{\mathrm{s}}=200, \mathrm{I}_{\mathrm{p}}=4 \mathrm{~A}, \mathrm{I}_{\mathrm{s}}= ? }
As \mathrm{\frac{\mathrm{I}_{\mathrm{p}}}{\mathrm{I}_{\mathrm{s}}}=\frac{\mathrm{N}_{\mathrm{s}}}{\mathrm{N}_{\mathrm{p}}} or \mathrm{I}_{\mathrm{s}}=\frac{\mathrm{N}_{\mathrm{p}}}{\mathrm{N}_{\mathrm{s}}} \mathrm{I}_{\mathrm{p}}=\frac{50}{200} \times 4 \mathrm{~A}=1 \mathrm{~A} }

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shivangi.shekhar

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