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The number of words that can be formed using only 3 alphabets if at least one of the letters from A, B, C, D, and E can be repeated.

 

Option: 1

45


Option: 2

35


Option: 3

25


Option: 4

55


Answers (1)

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The number of required words = The total number of words with repetition allowed - The number of words in which no alphabet is repeated


The\ required\ number\ of\ words=5^{3}- ^{5}P_{3}

5^{3}- ^{5}P_{3}=125-100=25

Therefore, the total number of ways is 25 ways.

 

Posted by

HARSH KANKARIA

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