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The order in which the following oxides are arranged according to decreasing basic nature is


 

Option: 1

\\\mathrm{Na}_{2} \mathrm{O}, \mathrm{MgO}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{CuO}\\


Option: 2

\mathrm{MgO}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{CuO}, \mathrm{Na}_{2} \mathrm{O}\\


Option: 3

\mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{MgO}, \mathrm{CuO}, \mathrm{Na}_{2} \mathrm{O}\\

 


Option: 4

\mathrm{CuO}, \mathrm{Na}_{2} \mathrm{O}, \mathrm{MgO}, \mathrm{Al}_{2} \mathrm{O}_{3}


Answers (1)

best_answer

The electropostive character generally increases from left to right along a period. With the increase in the metallic nature, the basic nature of oxide increases

Thus, the correct order is 

Na_2O > MgO > Al_2O_3 >CuO

Posted by

vishal kumar

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