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  • The order of magnitude of ionic radii of ions <img alt="{Na}^{+},{Mg}^{2+},{Al}^{3+}\: and\: {Si}^{4+}is" src="/latex-image/?%7BNa%7D%5E%7B&plus;%7D%2C%7BMg%7D%5E%7B2&plus;%7D%2C%7BAl%7D%5E

The order of magnitude of ionic radii of ions {Na}^{+},{Mg}^{2+},{Al}^{3+}\: and\: {Si}^{4+}is

Option: 1

{Na}^{+}<{Mg}^{2+}<{Al}^{3+}< {Si}^{4+}


Option: 2

{Mg}^{2+}<{Na}^{+}<{Al}^{3+}< {Si}^{4+}


Option: 3

{Al}^{3+}<{Na}^{+}<{Si}^{4+}< {Mg}^{2+}


Option: 4

{Na}^{+}>{Mg}^{2+}>{Al}^{3+}> {Si}^{4+}


Answers (1)

best_answer

As we have learnt, 

In isoelectronic species, as the positive charge increases, the radii decreases due to an increase in the effective nuclear charge.

Thus the correct order of radius is 

Na^+ > Mg^{2+}> Al^{3+}> Si^{4+}

Posted by

Gaurav

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