The oxidation number of Mn in is :
+5
+6
+7
+3
Let x be the charge on Mn.
So, 2x + 7 X (-2) = 0
2x -14 = 0
X= +7
Study 40% syllabus and score up to 100% marks in JEE
50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
JEE Main 2026 final key soon; objection window closes today
100 marks in JEE Mains 2026 Percentile: Know rank trends, admission chances at NITs, IIITs
NIT vs GFTI: Which requires a lower JEE Main cutoff?
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now