The oxidation number of Mn in is :
+5
+6
+7
+3
Let x be the charge on Mn.
So, 2x + 7 X (-2) = 0
2x -14 = 0
X= +7
Study 40% syllabus and score up to 100% marks in JEE
50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
JEE Main 2026: NTA reopens Session 2 registration; apply by March 13 at jeemain.nta.nic.in
JEE Mains 2026 LIVE: NTA session 2 city slip soon; admit card, exam dates, here's how to prepare
JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now