Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The point A lies on the circle \mathrm{(x+3)^2+(y-4)^2=r^2}. Two chords of lengths 13 and 15 are drawn to the circle through A such that the distance between the mid points of these chords is 7. Then \mathrm{r}=
 

Option: 1

\frac{45}{4}


Option: 2

\frac{70}{9}


Option: 3

\frac{32}{3}


Option: 4

\frac{65}{8}


Answers (1)

best_answer

\mathrm{r} is the circumradius of the triangle whose sides are  \mathrm{a=13, b=15, c=14}. \mathrm{r=\frac{a b c}{4 \Delta} }

Posted by

Ritika Harsh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question