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The point on the hyperbola \mathrm{3 x^2-4 y^2=72}  which is nearest to the

 line  \mathrm{3 x+2 y+1=0}  is

Option: 1

(-6,3)


Option: 2

(6,3)


Option: 3

(-6,-3)


Option: 4

(6,-3)


Answers (1)

best_answer

(a) :  \mathrm{3 x^2-4 y^2=72}

Since all the options (a), (b), (c), (d) are satisfies the

equation of hyperbola and (-6,3) is at the minimum

distance from line.(Using distance formula)

Posted by

Sanket Gandhi

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