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The point on the straight line \mathrm{x+y=2}, which is nearest to the circle \mathrm{x^2+y^2-10x+2y+22}

 

Option: 1

(1, 1)


Option: 2

 (4, -2)

 


Option: 3

 (-2, 9)


Option: 4

(3, -1)

 


Answers (1)

best_answer

Shortest distance between 2 curves occurs along the common normal. Let required point be (t, 2 -t). Normal at this will be 

y –(2 –t) = (x –t), it should passes through centre of circle so 

–1 –2 + t = 5 –t ⇒ t = 4, so point can be (4, -2).

 

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vinayak

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